c^2+5c+4=180

Solution for c^2+5c+4=180 equation:

c^2+5c+4=180

We move all terms to the left:

c^2+5c+4-(180)=0

We add all the numbers together, and all the variables

c^2+5c-176=0

a = 1; b = 5; c = -176;
Δ = b2-4ac
Δ = 52-4·1·(-176)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-27}{2*1}=\frac{-32}{2}
=-16
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+27}{2*1}=\frac{22}{2}
=11
$